Question

find the digit at the unit place of the number 7^2019 ​

Answer 1

Answer:

The answer will be 3

Step-by-step explanation:

As we know the ones digit of the square of no 7 will be

{7,9,3,1}

The Cyclicity table for 7 is as follows:

7^1 =7

7^2 =49

7^3 = 343

7^4 = 2401

So,the answer will be one of them.

If we divide 2019/4 then the remainder will be 3

Thus, the last digit of 7^2019 is equal to the last digit of 7^3 i.e. 3.

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