Find the dimensions of a rectangle with a perimeter of 112 cm if the length is 4 cm less than four times the width.
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Solution :
Perimeter of rectangle = 112 cm ----------------- (1st EQUATION)
let the width of rectangle be x cm
therefore length of rectangle = 4x - 4
We know that ,
Perimeter of rectangle = 2(length + width)
= 2 (4x - 4 + x)
=2 (5x - 4)
= 2*5x - 2*4
=10x - 8 ------------- (2nd equation)
From 1st and 2nd we get ,
112 = 10x - 8
or 112 +8 = 10x
or 120 = 10x
or 120/10 =x
or 12 = x
or x =12
hence width of rectangle = 12 cm
therefore , length of rectangle = 4x - 4 = 4*12 - 4 = 48 - 4 = 44 cm
Hope this helps You!!
Thank You!!
Cheers !!! :)
Perimeter of rectangle = 112 cm ----------------- (1st EQUATION)
let the width of rectangle be x cm
therefore length of rectangle = 4x - 4
We know that ,
Perimeter of rectangle = 2(length + width)
= 2 (4x - 4 + x)
=2 (5x - 4)
= 2*5x - 2*4
=10x - 8 ------------- (2nd equation)
From 1st and 2nd we get ,
112 = 10x - 8
or 112 +8 = 10x
or 120 = 10x
or 120/10 =x
or 12 = x
or x =12
hence width of rectangle = 12 cm
therefore , length of rectangle = 4x - 4 = 4*12 - 4 = 48 - 4 = 44 cm
Hope this helps You!!
Thank You!!
Cheers !!! :)
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