Question

Find the dimensions of rectangle whose perimeter is 28 and whose area is 40 square metres ? (PRIMARY SCHOOL SOLVING )

Answer 1

perimeter =2(l+b)=28

area=l*b=40

2l+2b=28

l+b=14

if l=10 then b=4

or l=4 then b=4

Answer 2

Answer:

Step-by-step explanation:

Here

Let length of rectangle is x

Let breadth be y

Then perimeter,

2x+2y=28

And x. y=40

After solving these eq's we get

Length and breadth