Question

find the discriminant of of the quadratic equation 3√3x^2+10x+√3=0.
plz be fast tomorrow is my exam.

Answer 1

as we know
D = b^2 - 4ac
so
$d = {10}^{2} - 4 \times (3 \sqrt{3} ) \times ( \sqrt{3} ) \\ thus \\ d = 100 - 36 = 64$
so value of discriminant is 64

hope it helps you
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Answer 2

D=b^2-4ac
= (10)^2-4×3root3×root3
=100-4×12×3
= 100-36
=64
Hope it helps......