Question

find the discriminant of the quadratic equation 3x²-6x-4=0 and hence find the nature of its roots

Answer 1

Answer:

from the above equation

we take

a = 3

b = -6

c = -4

to find discriminant

D = b^2 - 4ac

put a,b,c in formula

D = -6 ^2 -4(3)(-4)

= 36 - (-48)

D = 36 + 48 = 84

nature of root is real and unequal

Answer 2

The discriminant of given equation is 84 and hence, the equation have two real distinct solutions.          

Step-by-step explanation:

We are given the following quadratic equation in the question:

$3x^2-6x-4=0$

Comparing to general form of quadratic equation:

$ax^2 + bx + c = 0$

We get,

$a = 3\\b = -6\\c = -4$

We have to evaluate the discriminant for the given equation.

$D = b^2 - 4ac\\D = (-6)^2 - 4(3)(-4) \\D = 36 + 48\\D = 84$

$D > 0$

Since the discriminant is positive, the quadratic equation have two distinct real solutions.

#LearnMore

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