Question

find the distance between the point p ( -5,-4 ) and Q(3,-7)​

Answer 1

Answer:

√73

Step-by-step explanation:

D = Distance

D=

$\sqrt{(x {2}^{2} - x {1}^{2} ) + (y {2}^{2} - y {1}^{2} ) }$

x1 = -5

y1 = -4

x2 = 3

y2 = -7

Put the values it on formula:

answer is √73

Answer 2

$\huge\orange{\boxed{\underline{ANSWER}}}$

GIVEN

• There are two points P(-5, -4) and Q(3, -7)

FORMULA

• Distance between two points =

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

SOLUTION

• Distance =

$\sqrt{ {(3 + 5)}^{2} + {( - 7 + 4)}^{2} } \\ = \sqrt{ {(8)}^{2} + {( - 3)}^{2} } \\ = \sqrt{64 + 9} = \sqrt{73}$