Question

Find the distance between the points A(2,3) and B(6,-8).​

Answer 1

use formula

distance=root{(x2-x1)^2+(y2-y1)^2}

=root{(4)^2+(-11)^2}

=root (16+121)=root(137)

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Answer 2

Answer:

The distance between the two pints A=(2,3) and B=(6,-8) is $\sqrt{137}$

Step-by-step explanation:

Distance between two points:

• The distance between any points in a plane is the shortest distance between the two points.

       Let two points be A=(x₁,y₁), B=(x₂,y₂)

• The distance between two points is given by

        AB = $\sqrt{(x_{2}-{x_{1})^{2}+(y_{2}-{y_{1})^{2} }$

• Given points are A=(2,3) and B=(6,-8)

       where (x₁,y₁) = (2,3) and (x₂,y₂) = (6,-8)

       So, distance between the points A and B is

             AB = $\sqrt{(6-{2)^{2}+(-8-{3)^{2} }$

                   = $\sqrt{(4)^{2}+(-11)^{2} }$

                   = $\sqrt{16+121$

             AB = $\sqrt{137}$

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