Math, asked by Aishwarya00001, 1 year ago

Find the distance of point (-1,3) from the y axis.

Answers

Answered by DreamGirl01
4

Answer:

DISTANCE => 1UNIT

Step-by-step explanation:

**************** HEY DEAR **************

HERE IS YOUR ANSWER....


AM FINDING PERPENDICULAR DISTNCE HERE...

POINT PERPENDICULAR TO THIS POINT ON Y-AXIS IS ( 0 , 3)

SO DISTANCE

=> ROOT { (-1-0)^2 + (3-3)^2 }

=> ROOT 1

=> 1 UNIT..

*************************************************


HEY MATE U HAVE POSTED HALF QUESTION I HERE TOLD U HOW TO FIND PERPENDICULAR DISTANCE BY APPLYING DISTANCE FORMULAS YOU CAN ALSO DIRECTLY CALCULATE THE DISTANCE AS DISTANCE OF THE GIVEN POINT FROM Y- AXIS IS ALWAYS EQUAL TO THE MODE OF THE X CO ORDINATE..


HOPE IT HELPS YOU..

THANKS.

^_^


Aishwarya00001: no i have posted the complete question only
Aishwarya00001: But Thanks so much.
Aishwarya00001: can u plz answer my other questions they r on maths only
DreamGirl01: YEAH
Aishwarya00001: you can view on my profile to answer them
DreamGirl01: SORRY I LET A PERPENDICULAR POINT ON Y-AXIS
macmikhil: the answer of Dream girl is wrong
DreamGirl01: u can report it
Answered by macmikhil
8
point P(-1,3)
from y axis i.e Q(0,y)


By applying distance formula
 \sqrt{( - 1 - 0) ^{2}  + (3 - y) { }^{2} }

 \sqrt{1 + 9 +  {y}^{2} - 6y }

 =  \sqrt{10 +  {y}^{2} - 6y }
this is the answer

thank u

Aishwarya00001: thanks
Aishwarya00001: can you plz answer my other questions by viewing my profile. it will be very helpful
sionjaison2003: this is a wromg answer...
Similar questions