Question

Find the distance of the point( -1, 1) from the line 12(x + 6) = 5(y- 2).

Answer 1

I hope this will be helpful for you

Answer 2

Answer:

Distance of the point (-1,1) from line 12(x+6)=5(y-2) is 5 units

Step-by-step explanation:

The distance of a point P(m,n) to the line Ax+By+C =0 is given by

$d =\frac{| Am+Bn+C|}{\sqrt{A^{2} +B^{2} } }$

here m=-1 and n=1

and equation in given form is 12x+72=5y-10

12x-5y+82=0

here A=12  B=-5  C=82

now put these values in the formula

$d =\frac{| Am+Bn+C|}{\sqrt{A^{2} +B^{2}}}\\ \\ d =\frac{| 12 (-1)+(-5)(1)+82|}{\sqrt{(12)^{2} +(-5)^{2} } }\\ \\ \\ =\frac{|-12-5+82|}{\sqrt{144+25}} \\ \\ \\ =\frac{65}{13} units\\ \\=5 units$