Question

Reduce the given equations into intercept form and find their intercepts on the axes: 3y+2=0

Answer 1

Solution :

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Intercepts form :

Equation of a line whose

x - intercept = a ,

y - intercept = b is

x/a + y/b = 1

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Here ,

3y + 2 = 0

=> 3y = -2

Divide each term by -2 , we get

=> 3y/(-2) = (-2)/(-2)

=> 3y/(-2) = 1

=> y/(-2/3) = 1

=> x/(0/1) + y/(-2/3) = 1

Therefore ,

x - intercept ( a ) = 0

y - intercept ( b ) = -2/3

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