Reduce the given equations into intercept form and find their intercepts on the axes: 4x-3y=6
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Solution:
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we know the ,
Intercepts form :
Equation of a line whose
x - intercept is a and
y - intercept is b is
x/a + y/b = 1
****************************************
Here ,
4x - 3y = 6
divide each term by 6 , we get
4x/6 - 3y/6 = 6/6
=> 2x/3 - y/2 = 1
=> x/(3/2) + y/( -2 ) = 1
Therefore ,
x - intercept (a) = 3/2,
y - intercept (b) = -2
••••••
*******************"*********************
we know the ,
Intercepts form :
Equation of a line whose
x - intercept is a and
y - intercept is b is
x/a + y/b = 1
****************************************
Here ,
4x - 3y = 6
divide each term by 6 , we get
4x/6 - 3y/6 = 6/6
=> 2x/3 - y/2 = 1
=> x/(3/2) + y/( -2 ) = 1
Therefore ,
x - intercept (a) = 3/2,
y - intercept (b) = -2
••••••
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