Question

Find the distance of the point (1,2)from the mid point of the line segment joining the points (6,8), (2,4).

Answer 1

hello users ......

we have to find
 the distance of the point (1,2)from the mid point of the line segment joining the points (6,8), (2,4).

solution :-
at first
let the mid point of  (6,8), (2,4) is (x,y) 

here 
x =$\frac{( x_{1} + x_{2} )}{2}$
=  $\frac{(6 + 2)}{2}$
= 8/2 = 4 
and y=  $\frac{( y_{1} + y_{2} )}{2}$ 
= $\frac{(8 + 4)}{2}$ = 12 / 2= 6

the co-ordinates of mid point are (4,6) 

now,
 using distance formula 
distance between (4,6) and (1,2) is 
=  $\sqrt{( 1 - 4)^{2} +( 2 - 6 )^{2} }$ 
= √(3² + 4²) = √(9 + 16) = √ 25 = 5 answer 

∧∨ hope it helps ∧∨

Answer 2

we have to find

 the distance of the point (1,2)from the mid point of the line segment joining the points (6,8), (2,4).

solution :-

at first

let the mid point of  (6,8), (2,4) is (x,y) 

here 

x =

=  

= 8/2 = 4 

and y=   

=  = 12 / 2= 6

the co-ordinates of mid point are (4,6) 

now,

 using distance formula 

distance between (4,6) and (1,2) is 

=   

= √(3² + 4²) = √(9 + 16) = √ 25 = 5