Math, asked by razz71, 11 months ago

find the eighth and tenth terms of the series 2,4,8,16,...

Answers

Answered by Anonymous
0
r = 4/2 = 2

nth term = a*r^(n-1)

8th term = 2*2^7
=2^8 = 256

10th term = 2*2^9
=2^10 = 1024....
Hope this helps....
Answered by kuhu965
1
8 th= 256
and 10= 1024
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