Find the eleventh term from the last term of the AP: 27, 23, 19, ..., –65.
Avantika2003:
-23
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Answered by
3
We can reverse this finite A.P given =>-65,-61,-57,......,27 as the common difference is 4 when we reverse the A.p now A11 = A + 10d = -65+10*4 = -65 + 40 = -25.
Answered by
4
First of all, Reverse the AP
Now
a = -65
d = 4
11th term will be
an = a+(n-1)d
a11 = -65+10(4)
a11 = -65+40
a11 = -25
Now
a = -65
d = 4
11th term will be
an = a+(n-1)d
a11 = -65+10(4)
a11 = -65+40
a11 = -25
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