Question

find the empirical formula of a co.pound containing 17.64 % hydrogen and 82.35 % of nitrogen.

Answer 1

Given is the % of H n N

So atomic wt of H is 1

atomic wt of N is 14

Divide % of H with its atm. wt and similarly N % with its atm wt I.e. 14

You will get the relative no of atoms..

to get simplest ratio..Divide the smaller value of relative no of atoms with the two.....you will get the simplest ratio

NH3

Answer 2

1.Compound contains 17.7% hydrogen and 82.3% Nitrogen
i.e if 100g of the compound is present, 17.7g of Hydrogen and 82.3g of Nitrogen is present

2))Moles of hydrogen = 17.71=17.7
Moles of Nitrogen =82.314=5.88

3. We divide the mole value obtained by the smallest number ;
i.e   N: H5.885.88:17.75.88  1: 3

Hence the formula of the compound is NH3