Question

Find the energy in kwh in the month of september by 4 devices of power 100w each, if each one of them is used for 10 hr daily

Answer 1

a. the energy used in one hour at the rate of 1kW is 1kWh.

b. the energy used in 1 hour at the rate of 1 joule per second is 1 kWh. 1kWh = 3.6 * 10 raised to the power 6 joules

c. power of 4 devices in 30 days = 100w x 4 = 400w

time taken by 4 devices = 10 x 30 x 4 = 1200 h

so, energy = 400w x 1200h

= 480000 kWh

Answer 2

__HERE IS YOUR ANSWER__