Question

Find the equation of a circle whose touch the line x = 0 y = 0 and x = 6.

Answer 1

the circle touch the x-axis, y -axis and line x=6

therefore, radius of circle= 6/2= 3 units

also, distance of centre of circle from the axis is 3 units.

so, coordinates of centre of circle is (3,3)

hence, equation of circle is given by

${(x - 3)}^{2} + {(y - 3)}^{2} = {(3)}^{2} \\ {x}^{2} + {y}^{2} - 6x - 6y + 9 = 0$

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