Question

find the equation of a line passing through (-7,8)and(1,2).​

Answer 1

$- 7 + 1 = - 6 \\ 8 + 2 = 10$

Answer 2

4y-3x=0 is the eqn.........

Answer 3

U can do it using two point formula:
$(y - y1) = \frac{(y2 - y1)}{(x2 - x1)} (x - x1) \\ (y - 8) = \frac{2 - 8}{1 - ( - 7)} (x -( - 7)) \\ (y - 8) = \frac{ - 6}{8} (x + 7) \\ 8(y - 8) = ( - 6)(x + 7) \\ 8y - 64 = - 6x - 42 \\ 6x + 8y - 22 = 0$
Here's your answer.
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