Question

Find the equation of a line with x-intercept -3 and passing through the point (-2,5)

Answer 1

x-intercept is the point where the line cuts x axis so, the point will be 3,0

Answer 2

Answer:

The equation of the line is given by y = 5x + 15

Step-by-step explanation:

Given that x-intercept is -3, therefore the point on the x-axis is (-3, 0)

And another point on the line is (-2, 5)

Now we have two points to find the slope of line m consider,

$m=\frac{y_{2}-y_{2} }{x_{2}-x_{1} }$

$m=\frac{5-0}{-2-(-3)}$

$m=5$

Therefore the slope of the line is 5

Now consider Point-slope form to find equation of line

y - y1 = m (x -x1)

y - 5 = 5 (x -(-2))

y - 5 = 5x + 10

y = 5x + 15

Therefore the equation of the line is given by y = 5x + 15