Question

find the equation of line passing through a point (-3,-5) and parallel to x-2y-7=0

Answer 1

Slope of equation x-2y-7 = 0

m = -A/B = -1/(-2) = 1/2

Let the line be l

line l have the slope = m = 1/2

and passing point is (-3,-5)

Hence equation of Line l

(y-y1) = m(x-x1)

y-(-5) = (1/2)(x-(-3))

2(y+5) = x+3

2y+10-x-3 = 0

2y-x+7 = 0

=> x-2y-7 = 0

Answer 2

x-2y-7=0
A line parallel to it =( x-2y+k=0)
k is some constant
substitute the given points in d eqn (x-2y+k=0)
-3-(2)(-5)+k=0
-3+10+k=0
7+k=0
k= -7
the req eqn is x-2y+(-7)=0
therefore the eqn is x-2y-7=0