Math, asked by adarshrai04, 1 year ago

find the equation of line passing through the point (2,1,3) having direction ratios (1,1,-2)

Answers

Answered by VEDULAKRISHNACHAITAN
2

Answer:

(x-2)/1 = (y-1)/1 = (z-3)/-2

Step-by-step explanation:

Equation of the line passing through the point (a,b,c) and having direction ratios (l,m,n) is given by

           (x-a)/l = (y-b)/m= (z-c)/n .


Answered by nalinsingh
9

Hey !!

Let the point A (2 , 1 , 3) and a = 1 , b = 1 and c = -2. Since, we know that cartesian equation of straight line passing through the point ( x₁ , y₁ , z₁) having direction ratios a , b, c is

                  x - x₁ / a = y - y₁ / b = z - z₁ / c

Therefore, equation of required line is

                 \frac{x-2}{1} = \frac{y-1}{b} = \frac{z-3}{-2}


GOOD LUCK !!

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