Question

Find the equation of parabola whose vertex at the origin, the axis along the x-axis, and passes
through (-3, 6).

Answer 1

Final answer:

$\\\tt y= \dfrac{2x}{3}$

Steps:

For a parabola,

$\\\tt y = 4ax^2$

where a is the focus,

Using coordinates (-3,6).

$\\\tt 6 = (4)*a*(9)\\\\a= \dfrac{1}{6}$

Therefore the equation of  the parabola will be,

$\\\tt y = 4(\dfrac{1}{6})x \\y= \dfrac{2x}{3}$