Find the equation of parabola with focus ponts (-8,-2) and directrix y-2x+9=0?
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Answer:
PS =PM
PS is distance of point from focus
PM is perpendicular distance of point from a line
√(x+8)^2 + ( y+2)^2 = | -2x+y +9 / √ 4+ 1 |
Squaring on both side
X^2 +64 + 16x + y^2 + 4 y + 4 = (-2x+y+9)^2 / 5
= 4x^2 +y^2 +81 - 4xy + 18y - 36 x /5
5x^2 + 5y^2 + 20y + 80 x + 340 = 4x^2 + y^2 -4xy +18y -36x +81
Step-by-step explanation:
PS =PM
PS is distance of point from focus
PM is perpendicular distance of point from a line
√(x+8)^2 + ( y+2)^2 = | -2x+y +9 / √ 4+ 1 |
Squaring on both side
X^2 +64 + 16x + y^2 + 4 y + 4 = (-2x+y+9)^2 / 5
= 4x^2 +y^2 +81 - 4xy + 18y - 36 x /5
5x^2 + 5y^2 + 20y + 80 x + 340 = 4x^2 + y^2 -4xy +18y -36x +81
Step-by-step explanation:
Vidayanaca:
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