Question

find the equation of straight line whose length of perpendicular with origin is 6 and inclines at 60 with x axis.​

Answer 1

Answer:

x√3 - y +_ 12 = 0

Step-by-step explanation:

1) By using normal form

xcos● + ysin● = +_p

● is shown in the figure

● = 150

p = 6

Therefore,

x(-√3/2) + y(1/2) = +_6

x√3 - y _+12 = 0

2) By using formula of distance of a point from line:

Let the line be

y=mx + c

m=tan 60

m=√3

->y=√3 x + c

Distance of origin from line is 6

|{√3(0)-(0)+c}/2 |= 6

c = +_12

Therefore

y = √3x +_12