Question

find the equation of tangent to the circle X2 square + Y2 - 3x+2y=0 at the origin ​

Answer 1

Step-by-step explanation:

-3x +2y= 0 put X^2= xx'

Y^2= yy'

x',y'= 0

Answer 2

The equation of tangent at point (0,0) is given by

$y=\frac{3}{2}x$

Step-by-step explanation:

Equation of circle

$x^2+y^2-3x+2y=0$

Point (0,0)

$x_1=0,y_1=0$

Differentiate w.r.t x

$2x+2yy'-3+2y'=0$

$y'(2y+2)=3-2x$

$y'=\frac{3-2x}{2y+2}$

Slope at point (0,0)

$m=\frac{3-2(0)}{2(0)+2}=\frac{3}{2}$

Point-slope form

$y-y_1=m(x-x_1)$

Using the formula

The equation of tangent at point (0,0)

$y-0=\frac{3}{2}(x-0)=\frac{3}{2}$

The equation of tangent at point (0,0) is given by

$y=\frac{3}{2}x$

#Learns more:

https://brainly.in/question/10668379