find the equation of the bisector of the obtuse angle between the lines x+y-5=0 and x-7y+7=0
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Answered by
22
Answer:
-3x + y + 9 = 0
Step-by-step explanation:
x+y-5=0
=> -x - y + 5 = 0
x-7y+7=0
a₁a₂ + b₁b₂ = (-1)(1) + (-1)(-7) = - 1 + 7 = 6 > 0
=> the obtuse angle bisector
=> (a₁x + b₁y + c₁)/√(a₁² + b₁²) = (a₂x + b₂y + c₂)/√(a₂² + b₂²)
=> (-x - y + 5)/√2 = (x - 7y + 7)/√50
=> 5(-x - y + 5) = (x - 7y + 7)
=> -6x + 2y + 18 = 0
=> -3x + y + 9 = 0
Answered by
4
Answer:
-3x+y+9=0
Step-by-step explanation:
The step-by-step explanation is provided in the photo attached.
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