Question

find the equation of the line passing through the intersection of the line x+y-3=0 and2x-y+2=0 and parallel to the line 3x+y+4=0 represent the line of the graph sheet​

Answer 1

Answer:

3x+y=3 is the answer.

Step-by-step explanation:

if you like the answer then mark as brilliant

Answer 2

Answer:

Slope of 3x+4y−7=0

m

1

=−

x

y

=−

3

y

Since desired line passes through x−y+z=0 and 3x+y−10=0

On solving, x=2; y=0

Equation of line which is perpendicular to 3x+4y−7=0

m

2

(x−2)=(y−4), where m

2

is slope

m

2

=

4

3

(y−4)=

4

3

(x−2)

4y−16=3x−6

3x−4y+10=0