Question

find the equation of the line passing through the intersection of line 3x+y-9=0 and 4x+3y-7=0 and parallel to y-axis​

Answer 1

Answer:

To find point of intersection

solve equation of both lines

2x+y=5 …………(1)

x+3y+8=0 …………..(2)

Point of inter-section=(

5

23

,

5

−21

)

The required line is parallel to 3x+4y=7

Line parallel to ax+by+c

1

=0 is ax+by+λ=0 required line is 3x+4y+

i

^

=0

We know that it passes through (

5

23

,

5

−21

)

=3(

5

23

)−4(

5

21

)+λ=0

=−(

5

69

−

5

84

)=λ

λ=(−3)

⇒λ

⇒3x+4y+3=0.

Step-by-step explanation:

this is your answer hope it helps

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