Question

find the equation of the line which has x intercept =8 and is perpendicular to the line 3x+4y-17=0​

Answer 1

Answer:

3*8+4y-17=0

24+4y-17=0

7+4y=0

4y= -7

y = -7/4

Or

y= -1.75

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Answer 2

Answer:

4x-3y-32=0

Step-by-step explanation:

line has x-intercept=8

that means it cuts x axis at (8,0)

and the line is perpendicular to 3x+4y-17=0

slope of 3x+4y-17=0 is (-3/4)

and the line is perpendicular to the given line

m(-3/4)=-1

m=4/3

we have point (8,0) and slope (4/3)

therefore by slope point form

y-y1=m(x-x1)

y-0=(4/3)(x-8)

3y=4x-32

4x-3y-32=0

hence the required equation

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