Question

find the equation of the locus of points equidistant from (-2,0) and (-4,-2)​

Answer 1

Answer:

Solution

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Let the point be (h,k).

Given:

Distance of point from A=Distance of point from B

⟹

(h+3)

2

+(k−2)

2

=

h

2

+(k−4)

2

⟹(h+3)

2

+(k−2)

2

=h

2

+(k−4)

2

⟹h

2

+6h+9+k

2

−4k+4=h

2

+k

2

−8k+16

⟹6h−4k+13=−8k+16

⟹6h+4k=3

Replacing h with x and k with y:

6x+4y=3