find the equation of the parabola with vertex at (0,0) passing through (5,2)and symmetric with respect to y-axis.
Answers
Answered by
3
Since it is passing through (0,0) so eqn of parabola is
y^2=4ax----------------------------eq(1)
Since it is passing through( 5,2)
So
2^2=4ax5
4=20a
a=1/5
So reqd eqn is
y^2=4(x/5)
y^2=4x/5
y^2=4ax----------------------------eq(1)
Since it is passing through( 5,2)
So
2^2=4ax5
4=20a
a=1/5
So reqd eqn is
y^2=4(x/5)
y^2=4x/5
Similar questions