Question

find the equation of the straight line which passes through the point 3,1 and with gradient 3 hence find the coordinates of the point of intersection of the line one with the line y=x​

Answer 1

Step-by-step explanation:

Answer:

Given :-

Mass of object = 100 kg

Initial velocity = 5 m/s

Final velocity = 8 m/s

Time taken = 6 sec

To Find :-

Mounmentum

Magnitude

Force exerted

Solution :-

As we know that

\huge \tt \: P = mvP=mv

Here,

P denotes Mounmentum

M denotes Mass

V denotes Velocity

Firstly let's calculate initial Mounmentum

\huge \fbox{PI = mu}

PI = mu

Here,

PI = Initial Mounmentum

M = Mass

U = Initial Mounmentum

\tt \: PI = 100 \times 5PI=100×5

\tt \: PI = 500 \: mpsPI=500mps

Now,

Let's find final Mounmentum

As we know that

\huge \fbox{PF = mv}

PF = mv

Here,

PF = Final Mounmentum

M = Mass

V = Final Mounmentum

\tt \: PF = 100 \times 8PF=100×8

\tt \: PF = 800 \: mpsPF=800mps

Now,

Let's find Acceleration

\huge \boxed{ \bf \: A = \dfrac{v - u}{t}}

A=

t

v−u

Here,

A = Acceleration

V = Final Mounmentum

U = Initial Mounmentum

T = Time

\tt \: A = \dfrac{8 - 5}{6}A=

6

8−5

\tt \: A = \dfrac{3}{6}A=

6

3

\tt \: A = \dfrac{1}{2} \: = 0.5 \: mpsA=

2

1

=0.5mps

Now,

Let's find force exerted

\huge \fbox{F = ma}

F = ma

Here,

F = Force

M = Mass

A = Acceleration

\tt \: F = 100 \times 0.5F=100×0.5

\tt \: F = 50 \: NF=50N