Question

find the equation of the tangent to the circle x^2+y^2-4x+6y-12=0 which are parallel to x+y-8=0​

Answer 1

Answer:

given circle s= x^2+y^2-4x+6y-12=0......(1)

Step-by-step explanation:

the centre of the circle is (-g , -f) = (2,-3) the given line y = -x +8 so slope is m= -1. the radius of circle is= r = 5. to find equation of tangent parallel to given line use equation tangent to the circle(y-f) =m(x-g)+runder root (1+m^2)