Question

Find the equation of the tangent to the parabola y2=12xpassing through the point P(1,4)?

Answer 1

tangent is given by 
[tex] \frac{d}{dx} y^{2} = \frac{d}{dx} 12x [/tex]
$2y \frac{dy}{dx}=12$
$\frac{dy}{dx}= \frac{6}{y}$
but acc to the point(1,6)

Slope is 3/2

therefore eqn of line is y-4=3/2 (x-1)