Find the equations of the line through the point (4-5) and
(a) parallel to (b) perpendicular to the line 3x + 4y +5=0
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Step-by-step explanation:
the equation of a line parallel to 3x + 4y + 5 = 0 is of the form 3x +4y +k = 0
it passes (4 , -5)
3(4) +4(-5) +k = 0
12 -20 +k = 0
-8 +k =0
k = 8
∴ the required equation is 3x + 4y + 8 =0
(b) the equation of the line perpendicular to 3x +4y +5 = 0 is of the form
4x -3y +k = 0
it passes (4 , -5)
4(4) - 3(-5) + k = 0
16 + 15 + k = 0
31 + k = 0
k = -31
∴ the required equation is 4x -3y - 31 = 0
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