Question

Find the equivalent capacitance between points A and B of the assembly

Answer 1

The given figure forms a wheatstone bridge.

Hence the capacitance 5uF can be avoided.

Above capacitance:

C1=(1×2)/(1+2)

=2/3

below capacitance.

C2=(6×2)/(6+2)

=12/8

=3/2

so net Capacitance. C=C1+C2 =(3/2) +(3/2) =6/2 =3uF

Hope it helps...

Regards,

Leukonov/Olegion.