Question

find the equivalent resistance between a and B from the diagram given below​

Answer 1

Answer :

Equivalent resistance of series connection is given by

• R = R₁ + R₂ + ... + Rₙ

Equivalent resistance of parallel connection is given by

• 1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

Let's solve it step by step :

1) In upper arm two resistors of 3Ω and 2Ω are connected in series$.$

➝ R₁ = 3 + 2

➝ R₁ = 5Ω

2) In lower arm two resistors of 6Ω and 4Ω are also connected in series.

➝ R₃ = 6 + 4

➝ R₃ = 10Ω

3) Finally all three resistors of 5Ω, 30Ω and 10Ω come in parallel.

➝ 1/R = 1/R₁ + 1/R₂ + 1/R₃

➝ 1/R = 1/5 + 1/30 + 1/10

➝ 1/R = (12+2+6)/60

➝ R = 60/20

➝ R = 3Ω

Answer 2

Answer:

Equivalent resistance of series connection is given by

R = R₁ + R₂ + ... + Rₙ

Equivalent resistance of parallel connection is given by

1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

Now

[1] In upper arm two resistors of 3Ω and 2Ω are connected in series..

➳R₁ = 3 + 2

➳R₁ = 5Ω

[2] In lower arm two resistors of 6Ω and 4Ω are also connected in series.

➳R₃ = 6 + 4

➳ R₃ = 10Ω

[3] Finally all three resistors of 5Ω, 30Ω and 10Ω come in parallel.

➳ 1/R = 1/R₁ + 1/R₂ + 1/R₃

➳ 1/R = 1/5 + 1/30 + 1/10

➳ 1/R = (12+2+6)/60

➳ R = 60/20

➳ R = 3Ω