Question

Find the factors of the polynomials.
3y² - 2y - 1
3y²− ____+ y − ______

_____ (y – 1) + 1 (y – 1)

( y – 1) ( + 1)​

Answer 1

Answer:

$3 {y}^{2} - 2y - 1 \\ 3 {y}^{2} - 3y + y - 1 \\ 3y(y - 1) + 1(y - 1) \\ (y - 1)(3y + 1)$

Step-by-step explanation:

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Answer 2

Splitting the middle term ,

= 3y² - 3y + 1y - 1

= 3y ( y - 1 ) + 1( y - 1 )

= ( y - 1 )( 3y + 1 )

Step-by-step explanation:

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