Find the first four consecutive terms in ap whose sum is 12 and sum of third and fourth is 14
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d=4
a=-3
a2=a+d=-1
a3=a2+d=3
a4=a3+d=7
Hence,req. AP is -3,-1,3,7....
a=-3
a2=a+d=-1
a3=a2+d=3
a4=a3+d=7
Hence,req. AP is -3,-1,3,7....
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