Find the first, fourth, and eighth terms of the sequence. A(n) = −5 ∙ 3x − 1
Answers
Answered by
2
Welcome dear,
● Answer -
A(1) = -5
A(4) = -135
A(8) = -10935
● Explaination -
First term in series -
A(1) = -5 × 3^(1-1)
A(1) = -5 × 1
A(1) = -5
Fourth term in series -
A(4) = -5 × 3^(4-1)
A(4) = -5 × 3^3
A(4) = -5 × 27
A(4) = -135
Eighth term in series -
A(8) = -5 × 3^(8-1)
A(8) = -5 × 3^7
A(8) = -5 ×
A(8) = -10935
Hope this helps you...
● Answer -
A(1) = -5
A(4) = -135
A(8) = -10935
● Explaination -
First term in series -
A(1) = -5 × 3^(1-1)
A(1) = -5 × 1
A(1) = -5
Fourth term in series -
A(4) = -5 × 3^(4-1)
A(4) = -5 × 3^3
A(4) = -5 × 27
A(4) = -135
Eighth term in series -
A(8) = -5 × 3^(8-1)
A(8) = -5 × 3^7
A(8) = -5 ×
A(8) = -10935
Hope this helps you...
Answered by
0
Answer:
Step-by-step explanation:
Given Find the first, fourth, and eighth terms of the sequence.A(n) = −5 ∙3^n − 1
So first term of the sequence is x = 1
A(n) = A(1) = - 5 . 3 ^1-1 = - 5 . 3^0 = - 5
So fourth term is x = 4
A(n) = A(4) = - 5 .3^4 - 1 = - 5 . 3 ^3 = - 135
A(n) = A(8) = - 5 . 3^8 - 1 = - 5 . 3^7 = - 2187
So the numbers of the sequence are - 5, - 135 and - 2187
knjroopa:
sorry last number is -2187 x 5 = - 10,935
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