find the focal length and nature of lens which should be placed in contact with a lens of focal length 10cm so that the power of the combination becomes 5 diopter (minus 20 cm and concave) give the ans. in image
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Answer:
Explanation:
Power(P2) of lens with 10 cm focal length = 10010=10D
Let Power of the lens is P1
Total power of combination = P1 +P2
5D= P1 + 10D
P1 = -5D
focal length = −15=−0.2m⇒−20 cm
Power of the lens is negative so the given lens is concave lens
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