Question

Find the following arithmetic progression.
1/15,1/12,1/10,-------------------to 11tern in class 10 th​

Answer 1

Answer:

11th term = 7/15

Step-by-step explanation:

first term, a = 1/15

common difference = second term - first term

d = (1/12) - (1/15) = 1/60

theb 11th term = a+10d = (1/15) + (10/60) = 7/15

hope this will help you

Answer 2

Answer:

First term(a)=1/15

Common difference(d)=1/12-1/15=1/60

Number of terms(n)=11

Last term(tn)=?

By using formula,we have

tn=a+(n-1)d

t11=1/15+(11-1)×1/60

Or,t11=1/15+10/60

.:t11=7/30