Find the following products (2a+3b)(3a+2b)
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0
Answer:
Answer
(3a+
b
2
)(2a−
b
3
)=(3a)(2a)+(
b
2
)(2a)−(
b
3
)(3a)−(
b
2
)(
b
3
)
=6a
2
+(
b
4
−
b
9
)a−
b
2
6
=6a
2
+(−
b
5
)a−
b
2
6
=6a
2
−
b
5a
−
b
2
6
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