Question

find the force per unit area of a conductor carrying a surface density 2.5×10^-9c/sqcm of electric charge​

Answer 1

Answer:

Explanation:nA

Answer 2

The Force per unit area of a conductor is 35.31N/m².

Given:-

Surface density of electric charge (s) = 2.5*10-⁹ c/cm²

To Find:-

The Force per unit area of a conductor.

Solution:-

We can simply calculate the Force per unit area of a conductor by using the following procedure.

As

Surface density of electric charge (s) = 2.5*10-⁹ c/cm²

Force per unit area of a conductor (F) =?

Here first we have to change the Surface density into its Standard SI unit i.e. m² from cm².

So, s = 2.5*10-⁹*10⁴m² = 2.5*10-⁵c/m²

According to the formula,

$F = \frac{ {s}^{2} }{2Eo}$

$F = \frac{ {(2.5 \times {10}^{ - 5}) }^{2} }{2 \times 8.85 \times {10}^{ - 12} }$

$F = \frac{2.5 \times 2.5 \times {10}^{ - 10} }{2 \times 8.85 \times {10}^{ - 12} }$

$F = \frac{6.25 \times {10}^{ - 10} }{17.7 \times {10}^{ - 12} }$

$F = 0.3531 \times {10}^{2}$

$F = 35.31$

Hence, the Force per unit area of a conductor is 35.31N/m².

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