Question

Find the force required to train of mass 1000 kg up in an incline 1 in 50 with an acceleration of 2 m/square cofficient of friction between the train and the rails is 0.005

Answer 1

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So, Thé answer is -- · Here, m = 200 quintals = 200 X 100 kg sin θ = 1/50 ; a = 2 ms-2. Force of friction = 0.5 N per quintal. F = 0.5 X 200 = 100 ..

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Answer 2

Explanation:

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