find the four angles of a cyclic quadrilateral ABCD in which angle A = (2x-1)degree ,angle B=(y+5)degree,angle C=(2y+15)degree and angle D=(4x-7)degree
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we know that it is a cyclic quadrilateral therefore, A+C =180
so, 2x-1 + 2y +15 =180
2x+2y= 166
similarly, 4x+y=182
by this we can find x and y by elimination method
and then find the angles
thanks!
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