Math, asked by anshusuryav, 1 year ago

Find the general solution of 4sin^2α-8cosα+1=0

Answers

Answered by vrrunda

0

4sin^2(¢)-8cos¢+1=0

4(1-cos^2¢)-8cos¢+1=0

4-4xos^2¢-8cos¢+1=0

4cos^2¢+8cos¢-1=0

solve it and you will get your answer....

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