Question

find the general solutions of sin 0 = tan0​

Answer 1

Answer:

sinθ=tanθ

∴sinθ=cosθsinθ

∴sinθcosθ=sinθ

∴sinθcosθ−sinθ=0

∴sinθ(cosθ−1)=0

∴ either sinθ=0 or cosθ−1=0

∴ either sinθ=0 or cosθ=1

∴ either sinθ=0 or cosθ=cos0 ....[∵cos0=1]

The general solution of sinθ=0 sinθ=nπ,nϵZ and 

cosθ=cosα is θ=2nπ±α, where nϵZ

∴ the required general solution is given by

θ=nπ,nϵZ or θ=2nπ±0,nϵZ

∴θ=nπ,nϵZ or θ=2nπ,nϵZ

Step-by-step explanation:

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Answer 2

Answer:

simple.

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