Find the greatest no. of 6-digit which is a prefect square.
Answers
Answered by
34
The greatest 6-digit no is 999999
Now finding the square root of 999999
we get,
√999999=999.9995
Now since we need a perfect square
We find the square of the no 999 without considering the decimal places,
So now we have,
⇒999×999=998001
So, the greatest 6-digit number which is a perfect square is 998001.
Now finding the square root of 999999
we get,
√999999=999.9995
Now since we need a perfect square
We find the square of the no 999 without considering the decimal places,
So now we have,
⇒999×999=998001
So, the greatest 6-digit number which is a perfect square is 998001.
Answered by
13
The greatest 6-digit no is 999999
Now finding the square root of 999999
we get,
√999999=999.9995
since we need a perfect square
so do square of 999 without taking decimal places,
that is
⇒ 999² = 998001
Now finding the square root of 999999
we get,
√999999=999.9995
since we need a perfect square
so do square of 999 without taking decimal places,
that is
⇒ 999² = 998001
Anonymous:
hope it helps
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