Find the greatest number of 6 digits exactly divisible by 34 15 36
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solution :
the greatest number of 6 digits = 999999
first , we need to find the LCM of 24 , 15 and 36 and the divide 6 digits number 999999 by the LCM and subtract the remainder from 6 digits number 999999 .
24 , 15 & 36
24 = 2 × 2 × 3 × 3
15 = 3 × 5
36 = 2 × 2 × 3 × 3
LCM of 24 , 15 and 36 = 360
now 999999/360
quatient = 2777
reminder = 279
therefore , the remainder is 279 , hence the required number is
999999 - 279 = 99720
hence 999720 is the greatest number of 6 digits exactly divisible by 24 , 15 and 36 .
hope it's helpful to you .... ☺️☺️
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